z^2+iz+(1-3i)=0

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Solution for z^2+iz+(1-3i)=0 equation:


Simplifying
z2 + iz + (1 + -3i) = 0

Remove parenthesis around (1 + -3i)
z2 + iz + 1 + -3i = 0

Reorder the terms:
1 + -3i + iz + z2 = 0

Solving
1 + -3i + iz + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -3i + iz + -1 + z2 = 0 + -1

Reorder the terms:
1 + -1 + -3i + iz + z2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3i + iz + z2 = 0 + -1
-3i + iz + z2 = 0 + -1

Combine like terms: 0 + -1 = -1
-3i + iz + z2 = -1

Add '-1z2' to each side of the equation.
-3i + iz + z2 + -1z2 = -1 + -1z2

Combine like terms: z2 + -1z2 = 0
-3i + iz + 0 = -1 + -1z2
-3i + iz = -1 + -1z2

Reorder the terms:
1 + -3i + iz + z2 = -1 + -1z2 + 1 + z2

Reorder the terms:
1 + -3i + iz + z2 = -1 + 1 + -1z2 + z2

Combine like terms: -1 + 1 = 0
1 + -3i + iz + z2 = 0 + -1z2 + z2
1 + -3i + iz + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
1 + -3i + iz + z2 = 0

The solution to this equation could not be determined.

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